A = √3s2/4 , ds/dt = -2 , √3s2/4 = 100 --> s2 = 400/√3 and s = 20 / 4√3
dA/dt = (√3s / 2) · ds/dt = -20/√3
Kyle B.
asked 03/20/21I need help with the following question:
The side of an equilateral triangle decreases at the rate of 2 cm/s. At what rate is the area decreasing when the area is 100 cm2?
A = √3s2/4 , ds/dt = -2 , √3s2/4 = 100 --> s2 = 400/√3 and s = 20 / 4√3
dA/dt = (√3s / 2) · ds/dt = -20/√3
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Kyle B.
Could you explain how you got to the final answer? I try to solve dA/dt= (√3s / 2) (-2) where s= 20 / 4√3 and I get a different answer.03/21/21