there is a point between p(1,0) and q(e,1) on the graph of y= ln x such that the tangent to the graph at the point is parallel to the line through points p and q. the x-coordinate of this point is?

Answer 1

The slope for the pq line is (1-0)/(e-1) = 1/(e-1) = m

Tangent of y is dy/dx = 1/x

To be parallel, dy/dx = m

1/x = 1/(e-1)

x = e-1