differentiate the following function

Question

Answer 1

Let's write the function as y = -1(2x³-3)^(-1/2)

Then use the product rule: y'(x) = -1(-1/2)(2x³-3)^(-3/2)(6x²) = (3x²)(2x³-3)^(-3/2) = (3x²)/(2x³-3)^(3/2)