Use l'hopitals rule to evaluate the limit or state it does not apply

Question

1. Lim x->-1 (x^3+x+2)/(x^4-2x-3)
2. lim x->1 (e^x -e)/Inx

Answer 1

1) This is a 0/0 situation, so we can use l'hopital

lim x->-1 -1(3x²+1)/(4x³-2) = -4/-6 = 2/3

2) This is also a 0/0 situation

lim x->1 e^x/(1/x) = e¹/(1/1) = e