
Yefim S. answered 03/16/21
Math Tutor with Experience
Let f(x) = (x)1/3; f(8) = 81/3 =2. We have tangent point (8, 2). Now equation of tangent line: f'(x) = 1/3x-2/3;
f'(8) = 1/3(8)-2/3 = 1/12; So y = 2 + 1/12(x - 8); y = 1/12x + 4/3
Linear approximation L(x) = x/12 + 4/3.
Now x = 8.1; L(12) = 8.1/12 + 4/3 = 2.0083.
So 81/3 ≈ 2.0083