Rewrite 4 sin theta cos 2 theta as a sum or difference

Question

How would I go about using the product-to-sum identity to figure this out?

Michael J. · Accepted Answer

4sinθcos2θ
 
 
cos(2θ) can be rewritten as   cos2θ - sin2θ
 
4sinθ[cos2θ - sin2θ]
 
 
We will get everything in terms of sinθ.
 
Remember that sin2θ + cos2θ = 1
 
4sinθ[1 - sin2θ - sin2θ] =
4sinθ[1 - 2sin2θ]

Rewrite 4 sin theta cos 2 theta as a sum or difference

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Rewrite 4 sin theta cos 2 theta as a sum or difference

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

Verify the identity cos^3xsin^2x = (sin^2x-sin^4x)cosx

Verify the identity tanx+coty/tanxcoty = tany+cotx

2sec^x-2sec^2x sin^2x

prove the following trigonometric identity

(cos^2x+1+sinx)/(cos^2x+3)=(1+sinx)/(2+sinx)

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