Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y = x^8, y = 1; about y = 4

Answer 1

I got 38.767. I did the pi times the integral from -1 to 1 of ∫((4-x^8)^2-(4-1)^2)dx. Let me know if this helped or if you still have questions :)