Yefim S. answered 03/16/21
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x = y2 - 1, 0 ≤ x ≤ 15; y = ±(1 + x)1/2 ;
A = 2π∫015[(1 + x)1/2(1 + 1/[4(1 + x)])1/2dx = π∫015( 5 + 4x)1/2 = π/4·2/3(5 + 4x)3/2015 =
π/6[653/2 - 53/2) = 268.54