Peter K. answered 13d
Math Tutor: SAT, ACT, GRE, Algebra, Discrete, Precalc, Algorithms
Let x be the amount charged. The expected profit for the insurance company is computed as follows: With probability 1/200, they lose $300,000, and with probability 1 – 1/200 = 199/200, they gain x dollars. The expected value is the sum of the products of the probabilities with the profits in each case, so the expected profit would be
E(Profit) = (1/200)(-300,000) + (199/200)(x)
= 199x/200 - 1500.
If we want this to be positive, we need this amount to be greater than 0, which gives this inequality:
199x/200 - 1500 > 0, which gives
199x/200 > 1500. Now multiply both sides by 200/199:
x > (200/199) * 1500, and this is approximately
x > $1,507.54.
If we also want this to be less than $500, we solve this:
199x/200 – 1500 < 500, so
199x/200 < 2000, and so
x < (200/199) * 2000, and this is approximately
x < $1020.05
For the expected profit to be greater than $1,500, we get:
199x/200 – 1500 > 1500
Solving as above yields approximately
x > $3,015.08
For the expected profit to be between $500 and $1000, we solve these inequalities:
500 < 199x/200 – 1500
and
$199x/200 – 1500 < 1000.
Following the same procedure as above yields
$1,020.05 < x < $2,512.56