We must find real numbers a and b so that a<12, -12> + b<4, 4> = <72, 0>
So, 12a + 4b = 72 and -12a + 4b = 0.
From the second equation, a = (1/3)b.
Thus, 12(1/3)b + 4b = 72
8b = 72
So, b = 9 and a = 3
That is 3<12, -12> + 9<4, 4> = <72, 0>
The coordinate vector is <3, 9>.