
Yefim S. answered 03/12/21
Math Tutor with Experience
At the end points of interval [0, 2] f(0) = 2cos0 = 2 = 2cos2π = f(2).
f(x) continuis on [0, 2] and differentiable on (0, 2).
So by Rolle's Theorem f'(c) = - 2πsinπc = 0; sinπc = 0; πc = π; c = 1