Given that x^3y^2=ax+y, express y′ in terms of x and y (a is a constant)

Answer 1

x³y² = ax + y

3x²y² + 2x³y(dy/dx) = a + dy/dx

(2x³y - 1)(dy/dx) = a - 3x²y²

dy/dx = (a - 3x²y²) / (2x³y - 1)