(sin 𝜋x + cos 𝜋y)3 = 49
3 (sin 𝜋x + cos 𝜋y)2 ( 𝜋 cos 𝜋x - 𝜋 sin 𝜋y dy/dx ) = 0
𝜋 cos 𝜋x - 𝜋 sin 𝜋y dy/dx = 0
- 𝜋 sin 𝜋y dy/dx = - 𝜋 cos 𝜋x
dy/dx = cos 𝜋x / sin 𝜋y
Oluwatobi L.
asked • 03/09/21Find dy/dx by implicit differentiation.
(sin 𝜋x + cos 𝜋y)3 = 49
dy/dx =
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