We derive formulas for the derivatives of simple functions, products, quotients and then the chain rule so that we NEVER have to do problems like this!!!!!
However, the answer is: limit as x->π [(x+h)2ecos(x+h)-x2ecos x}/(x+h)
Ash L.
asked 03/07/21We derive formulas for the derivatives of simple functions, products, quotients and then the chain rule so that we NEVER have to do problems like this!!!!!
However, the answer is: limit as x->π [(x+h)2ecos(x+h)-x2ecos x}/(x+h)
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