The integral is -51/x3.
I will leave the evaluation at the limits of integration to you.
I made a terrible mistake and I am sorry. The answer I gave you is dead wrong! Again I apologize.
The integral is -17/x2 which evaluates to (17/2t2)-17
Elle B.
asked • 03/05/21find area under curve y=17/x^3 from x=1 to x=t
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Elle B.
thank you! I got -51(-1/2t^2 +1/2) but it says it is wrong? I am not sure what i did incorrectly!03/05/21