
Yefim S. answered 03/01/21
Tutor
5
(20)
Math Tutor with Experience
dy/dx = (dy/dt)/(dx/dt) = (- 3t2 + 2t)/(- 2t-4) = (3t6 - 2t5)/2.
answer is (3t6 - 2t5)2
Bob M.
asked 03/01/21Find for the parametric equations
and y = -t3 + t2.
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Yefim S. answered 03/01/21
Math Tutor with Experience
dy/dx = (dy/dt)/(dx/dt) = (- 3t2 + 2t)/(- 2t-4) = (3t6 - 2t5)/2.
answer is (3t6 - 2t5)2
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