Yefim S. answered 03/01/21
Math Tutor with Experience
Intersection: 2 - x = √x; 4 - 4x + x2 = x; x2 - 5x + 4 = 0; x = 1 or x = 4 . we have to reject x = 4
V = ∫01(2 - x - √x)2dx = ∫01(4 + x2 + x - 4x - 4√x + 2x√x)dx = (4x + x3/3 - 3x2/2 - 8/3x3/2 + 4/5x5/2)01 =
4 + 1/3 - 3/2 - 8/3 + 4/5 = 29/30