Mark M. answered • 03/01/21
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Average value = [1 / (5-1)] ∫(from 1 to 5) x2dx
= (1/12) [ 53 - 13] = 124/12 = 31/3
Afshan H.
asked • 02/28/21Find the average value of f(x)=x^2 on the interval [1, 5]
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