The critical points are where the derivative of the function is zero or undefined.
In this case, the derivative is 2/(x-1)^(1/3) which is never 0 and is undefined at 1.
For the interval [0,2], both 0 and 2 are maxima (always try the endpoints and x=1 is a minimum. If you graph the function, it looks like a curvy v, with a cusp at one on the x axis. Had 0 and 2 not been included or if the range was all Real, there would be no maxima.