Yefim S. answered 02/26/21
Math Tutor with Experience
Let V is volume of water: V = 1/3hA; A/16 = h2/49; A = 16h2/49 and V = 16h3/147;
dV/dt = 48h2(dh/dt)/147 = 16h2(dh/dt)/49; dh/dt = (dV/dt)·49/(16h2) = 35cm3/s·49/(16·16cm2) = 6.7 cm/s
Esther K.
asked 02/26/21An inverted pyramid is being filled with water at a constant rate of 35 cubic centimeters per second. The pyramid, at the top, has the shape of a square with sides of length 4 cm, and the height is 7 cm. Find the rate at which the water level is rising when the water level is 4 cm.
Yefim S. answered 02/26/21
Math Tutor with Experience
Let V is volume of water: V = 1/3hA; A/16 = h2/49; A = 16h2/49 and V = 16h3/147;
dV/dt = 48h2(dh/dt)/147 = 16h2(dh/dt)/49; dh/dt = (dV/dt)·49/(16h2) = 35cm3/s·49/(16·16cm2) = 6.7 cm/s
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