The tangent line to the graph of y = x^3 at the point​ (x,y) has slope 3x^2. Using this​ result, find the slope of the curve at the point (3,27).

Question

The slope of the curve at the point (3,27) is ______ (Answer)?

Answer 1

the slope of tangent at that line is given by the equation of the slope: 3x²

at point (3,27) the slope is: 3(3)² = 3(9) = 27

hope that helps!