Write the equation of the tangent line to the graph of y=x^2 at the point x=1.2.

Question

_______ (Type An Equation).

Answer 1

When x=1.2 (6/5) then y=36/25

The slope at x=6/5 is 2*6/5=12/5

The point slope form is 12/5 = [y-(36/25)]/[x-(6/5)]

The fractions are a nuisance, so BE CAREFUL!

I am not sure where your confusion is.

The point slope form may look unfamiliar, but it is just messy with all those fractions.

Try it this way:

First write a single fraction in the numerator and denominator and then invert the denominator to get

12/5=(25y-36) * 5 /[25*(5x-6)]

Now multiply by 5 and divide out the 25

12=(25y-36)/(5x-6)

Now cross multiply

60x-72=25y-36

Now you should be able to get it into a form comfortable for you.