
Bradford T. answered 02/25/21
Retired Engineer / Upper level math instructor
The three hypotheses of Rolle's theorem are:
(i) f(x) is continuous on [a,b]
(ii) f(x) is differentiable on (a,b)
(iii) f(a) = f(b)
1) If you graph f(x), you can see that it is continuous, i.e. no breaks on the interval [0,81]
2) f(x) is differentiable on (0,81)
f '(x) = 1/(2√x) - 1/9 which exists on the open interval (0,81)
3) f(0) = f(81) = √81 - 81/9 = 9-9 = 0
Rolle's Conclusion:
f'(c) = 0
f'(c) = 1/(2√c) -1/9 = 0
(9 - 2√c)/(18√c) = 0
√c = 9/2
c = 81/4
There is only one number c = 81/4 which satisfies f '(c) = 0