f'(x)=3x2-6x+C
When x=2, f'(x)=0 means C=0
f(x)=x3-3x2+D
f(x)=0 => D=4
i.e. f(x)=x3-3x2+4
Rin A.
asked 7df'(x)=3x2-6x+C
When x=2, f'(x)=0 means C=0
f(x)=x3-3x2+D
f(x)=0 => D=4
i.e. f(x)=x3-3x2+4
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.