det(A) = (λ - 3)(λ + 7) - (-9) = λ2 + 4λ - 12 = 0
(λ + 6)(λ - 2) = 0
λ = -6 or 2
Louis Alain P.
asked 02/23/21λ1=
λ2=
det(A) = (λ - 3)(λ + 7) - (-9) = λ2 + 4λ - 12 = 0
(λ + 6)(λ - 2) = 0
λ = -6 or 2
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