f(x)= 4x^3-5x^2-x-1 find the slope at (1,-3) and (0,-1)

Answer 1

f(x) = 4x³ - 5x² - x - 1

f'(x) = 12x² - 10x - 1

Slope at the point (1, -3) = f'(1) = 12 - 10 - 1 = 1

Slope at the point (0, -1) = f'(0) = -1

Answer 2

slope = the derivative = 12x^2 -10x -1

plug in the x coordinate to find slope at a point

at (1,-3) slope = 12-10-1 = 1

at (0,-1) slope = -1

y coordinate is useful to make sure the point really is on the curve

f(1) = 4-5-1-1 = 3

f(0) = -1