Yefim S. answered 02/22/21
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By conjugate zero theorem -i and -2i are zeros also; in factored form f(x) = a(x - i)(x + i)(x - 2i)(x + 2i) =
a(x2 + 1)(x2 + 4); now f(-1) = a(1 + 1)(1 + 4) = 10a = 30; a = 3.
f(x) = 3(x2 + 1)(x2 + 4) = 3x4 + 15x2 + 12.