Draw a diagram to verify that the lower bound of integration is x = -1.
We need to integrate the cross-sectional area over the interval [-1 ,1] to get the requested volume:
∫-11 (√x+1)2dx
= ∫-11 (x+1)dx
1/2x2 + x ]-11 = 3/2 - (-1/2) = 2
Fauzi A.
asked 02/20/21The base of a solid is bounded by the curve , the x-axis and the line x = 1. The cross sections, taken perpendicular to the x-axis, are squares. Find the volume of the solid.
A. 1
B. 2
C. 2.333
D. None of these
Draw a diagram to verify that the lower bound of integration is x = -1.
We need to integrate the cross-sectional area over the interval [-1 ,1] to get the requested volume:
∫-11 (√x+1)2dx
= ∫-11 (x+1)dx
1/2x2 + x ]-11 = 3/2 - (-1/2) = 2
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