The antiderivative of 16-2x is 16x-x2
From 0 to b the integral is 16b-b2
From b to 8 (where the integrand crosses the x axis) the integral is 64-16b+b2.
Set these two expressions equal to each other and solve for b.
Sam C.
asked 02/19/21Find the value(s) of b if the vertical line x=b divides the region between y=16-2x and x and y-axis into 2 equal areas.
The antiderivative of 16-2x is 16x-x2
From 0 to b the integral is 16b-b2
From b to 8 (where the integrand crosses the x axis) the integral is 64-16b+b2.
Set these two expressions equal to each other and solve for b.
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