Let’s walk through it step by.
(1) What’s the probability that Tom is given any task?
There are 11 total board members.
5 tasks are assigned randomly.
We want the probability that Tom is chosen for one of those tasks.
Total ways to choose 5 people from 11:
C(11, 5) = 462
Favorable outcomes (Tom is included):
Fix Tom, then choose 4 more from the remaining 10 →
C(10, 4) = 210
So:
P(Tom gets a task) = 210 ÷ 462 = 35 ÷ 77 ≈ 0.4545
(2) What’s the probability that Tom is given the advertising task?
There are 5 tasks and 11 board members.
Each task is assigned randomly to one person.
So the chance that Tom gets any specific task (like advertising meetings) is:
P(Tom gets that task) = 1 ÷ 11 ≈ 0.0909