
Yefim S. answered 02/19/21
Math Tutor with Experience
Volume of water is V = 1/3πr2h; h/r = 6/2 = 3; r = h/3;
V = 1/3πh3/9 = πh3/27.
dV/dt = c - 11000, where c in cm3/min;
πh2/9·dh/dt = c - 11000; c = 11000 + π(200)2/9·20 = 290252.68 cm3/min
Cha'lie B.
asked 02/19/21Water is leaking out of an inverted conical tank at a rate of 11,000 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate at which water is being pumped into the tank. (Round your answer to the nearest integer.)
cm3/min
Yefim S. answered 02/19/21
Math Tutor with Experience
Volume of water is V = 1/3πr2h; h/r = 6/2 = 3; r = h/3;
V = 1/3πh3/9 = πh3/27.
dV/dt = c - 11000, where c in cm3/min;
πh2/9·dh/dt = c - 11000; c = 11000 + π(200)2/9·20 = 290252.68 cm3/min
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