Daniel B. answered 02/19/21
A retired computer professional to teach math, physics
After a time t
the first car will be at the point 48t South of the starting point,
the other car will be at the point 20t West of the starting point.
Since their directions are perpendicular, their distance after time t is
√((48t)² + (20t)²) =
√(2304t² + 400t²) =
52t
Therefore their distance always increases at the constant rate of 52 mi/h.