
Yefim S. answered 02/17/21
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f(x,y) = e^(x2y); ∂f/∂y(x,y) = e^(x2y)·x2; ∂f/∂y(x,0) = e^(x2·0)·x2 = 1·x2 = x2.
Answer: x2.
Brian J.
asked 02/17/21Consider . Compute
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Yefim S. answered 02/17/21
Math Tutor with Experience
f(x,y) = e^(x2y); ∂f/∂y(x,y) = e^(x2y)·x2; ∂f/∂y(x,0) = e^(x2·0)·x2 = 1·x2 = x2.
Answer: x2.
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