Set the derivative equal to 0: 4x3--12x2=0,,,there is a minimum at x=3.
At x=0, the graph is so steep it is hard to tell exactly what is happening, maybe a point of inflection,,,but apparently not a horizontal tangent.
Melissa E.
asked 02/16/21Find the coordinates of points where the graph of f(x) = x4 − 4x3 + 7 has horizontal tangents. As a check, graph f(x) and see whether the points you found look as though they have horizontal tangents.
( x , y ) = ( ? , ? ) (larger x-value)
Set the derivative equal to 0: 4x3--12x2=0,,,there is a minimum at x=3.
At x=0, the graph is so steep it is hard to tell exactly what is happening, maybe a point of inflection,,,but apparently not a horizontal tangent.
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