Yefim S. answered 02/17/21
Math Tutor with Experience
(i + j) x (j + k) = i x j + i x k + j x j + j x k = k - j + 0 - i = k - i - j
(k - i - j) · (j + k) = 0 + 1 - 0 - 0 - 1 - 0 = 0
Answer: 0
Taha A.
asked 02/16/21Calculate ((i + j) × (j + k)) · (i + k), if it exists. If it does exist, show all your steps and explain what the result means geometrically. If it does not exist, explain in detail why it does not exist.
Yefim S. answered 02/17/21
Math Tutor with Experience
(i + j) x (j + k) = i x j + i x k + j x j + j x k = k - j + 0 - i = k - i - j
(k - i - j) · (j + k) = 0 + 1 - 0 - 0 - 1 - 0 = 0
Answer: 0
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Luke J.
Your result is incorrect because j X k = +i not -i. And the significance of your answer was not explained, even if you had a mistake in it.02/18/21