Differentiate: dy/dx y=x^3/4-2x+1

Answer 1

Recall that if y=xⁿ, then dy/dx = nx^n-1

Using the above, we find that when y=x^3/4-2x+1,

dy/dx = d/dx(x^3/4-2x+1) = d(x^3/4)/dx -d(2x)/dx + d(1)/dx = 3/4x^(3/4-1) - 2 + 0 = 3/4x^-1/4 - 2