Given: s = 50 + 11t + 0.04*t^3
s = meters, t = seconds
Find: Acceleration of particle when t = 4
Solution:
Acceleration is the second derivative.
s = 50 + 11t + 0.04*t^3
s' = 11 + (0.04)*(3)*t^2
s'' = (0.04)*(3)*(2)*t
s'' = (.24)*t
s'' = (.24)*(4) When t = 4
s'' = .96
When t = 4, acceleration is .96 m/s^2