
Bradford T. answered 02/13/21
Retired Engineer / Upper level math instructor
The volume, V, of a square pyramid is:
V = a2h/3 Where h is the height and a is a base edge. The base edge increases in size as the pyramid fills.
The rate of the Volume is given as 75 cm3/s.
The problem is to find the rate, dh/dt, that the water is rising when the water level is 13 cm.
If you look at one side of the pyramid, there are two nested, similar triangles. For the big triangle, h=15 and a = 8. For any height of water level, by similar triangles,
a/h = 8/15 --> a = 8h/15. So our volume formula is now.
V = (8h/15)2h/3 = (64/225) h3/3
dV/dt = (64/225)(3h2 dh/dt)/3 = (64/225)h2 dh/dt
Solving for dh/dt:
dh/dt = (225/64)(1/h2)dV/dt
when h = 13
dh/dt = (225/(64•132))(75) = 1.560 cm3/s