The solution set is of the equation sec x = cos x on [0, 2π] is

Question

do i separate each and set to 0?

then look on the unit circle for the values?

sometimes I have trouble figuring out what the problems is actually asking me to find. thanks for any info

Answer 1

secx = cosx; cos²x = 1; cosx = 1 or cosx = -1

cosx = 1 x = 0 or x = 2π

cos x = -1 x = π

Answer 2

The equation given is cos²x = 1 between 0 and 2 pi.

So you need to know the values of x for which cos x = plus or minus 1.

so x = 0, pi and 2 pi.