Michael K. answered 02/09/21
PhD professional for Math, Physics, and CS Tutoring and Martial Arts
Since we know the volume of a sphere we can use this to determine the rate of change of volume with respect to time.
V = 4/3 * π * r3
dV/dt = 4/3 * π * d/dt (r3) = 4/3 * π * (3 * r2 * dr/dt) = 4 * π * r2 * dr/dt
At a specific time, the radius is 32 feet and is expanding at 3 ft/hour (assumed same time unit since not given).
Therefore, the change in volume is
dV/dt = 4 * π * (32)2 * 3 ft/hr = 12,288 * π ft/hr