dh/dt = + 1.5 , dA/dt = + 4.5. , h = 9 , A = 80 so b = 160 / 9.
A = 1/2 bh
dA/dt = 1/2(h·db/dt + b·dh/dt)
4.5 = 1/2 (9db/dt + 80/3)
9 = 9db/dt + 80/3
-53/3 = 9 db/dt
db/dt = - 53 / 27 cm/min
Sufyan M.
asked 02/09/21The height of a triangle is increasing at a rate of 1.5 centimeters/minute while the area of the triangle is increasing at a rate of 4.5 square centimeters per minute. At what rate is the base of the triangle changing when the height is 9 centimeters and the area is 80 square centimeters?
dh/dt = + 1.5 , dA/dt = + 4.5. , h = 9 , A = 80 so b = 160 / 9.
A = 1/2 bh
dA/dt = 1/2(h·db/dt + b·dh/dt)
4.5 = 1/2 (9db/dt + 80/3)
9 = 9db/dt + 80/3
-53/3 = 9 db/dt
db/dt = - 53 / 27 cm/min
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