Probably easier to differentiate after first rewriting the function as a fraction the radical:
s(x) = √((x+7)/(x)) and, further simplifying, s(x) = (1 + x-1)1/2
We need to apply chain rule: ds/dx = - 1/x2·(1/2)·(1 + x-1)-1/2 or -1/(2x2√(1 + x-1))
Alice S.
asked 02/06/21s(x)=x+7/
x
s^1(x)=
Probably easier to differentiate after first rewriting the function as a fraction the radical:
s(x) = √((x+7)/(x)) and, further simplifying, s(x) = (1 + x-1)1/2
We need to apply chain rule: ds/dx = - 1/x2·(1/2)·(1 + x-1)-1/2 or -1/(2x2√(1 + x-1))
s'(x) = d/dx (√x ) + d/dx (7/√x)
= d/dx(x1/2) + d/dx ( 7 x-1/2)
= 1/2 x-1/2 - 7/2 x-3/2
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