Does series 1/e^n conditionally converge?

Question

Does series 1/e^n conditionally converge?

Answer 1

Series 1/eⁿ converges, becouse 0 < 1/eⁿ < 1/n² starting from n = 1, and by comparisson test series 1/eⁿ

converges and because 1/e^n > 0 this convergence is absolute and conditional at the same time

.,

Answer 2

This is a geometric series with common ratio, r, of 1/e . This value of r is less than 1, so the series converges.

The sum is e /(e -1)