Mark M. answered 02/04/21
Tutor
4.9
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
(3x+1) / (x2+6x+8) = (3x+1) / [(x+4)(x+2)] = A / (x+4) + B / (x+2)
Nic C.
asked 02/04/21.
Which of the following integrals can be integrated using partial fractions using linear factors with real coefficients?
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None of these |
Mark M. answered 02/04/21
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
(3x+1) / (x2+6x+8) = (3x+1) / [(x+4)(x+2)] = A / (x+4) + B / (x+2)
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