Find the vertices of the ellipse centered at the origin with eccentricity e=1/5 and foci at (−4,0)and (4,0).

Answer 1

We have c = 4; e = c/a; a = c/e = 4/(1/5) = 20, b² = 20² - 4² = 384; b = √384 = 8√6

So vertices of ellypse are: (± 20, 0) and (0, ± 8√6)