
William W. answered 02/03/21
Experienced Tutor and Retired Engineer
To find minimums and/or maximums, take the derivative to find critical points:
f '(x) = 7cos(x) + 9sin(x) then set it equal to zero
7cos(x) + 9sin(x) = 0
7cos(x) = -9sin(x)
-7/9 = sin(x)/cos(x) [applicable only if cos(x) = 0 is not a solution, which it is not.
-7/9 = tan(x)
x = tan-1(7/9)
x = 2.481 + 2πk where k is any integer
and x = 5.622 + 2πk where k is any integer
To determine if these are minimums and/or maximums, take the 2nd derivative:
f ''(x) = -7sin(x) + 9cos(x)
f ''(2.481) is negative therefore the function is concave down and the critical point is a maximum and this will occur at all other multiples so f(x) has a maximum at x = 2.481 + 2πk where k is any integer.
f ''(5.622) is positive meaning the function is concave up and x = 5.622 is a minimum.(as well as all multiples of it.
Perhaps I fell into the trap because I didn't see the trip-up unless it was the need to use the multiple maximum generator of + 2πk.