Paul M. answered 02/03/21
A rational fraction may be written as a sum of partial fraction as follow:
1/[x(x-1)(x+3)] ≡ (A/x) + [B/(x-1)] + [C/(x+3)]
This equation must be IDENTICALLY true which means that the coefficients of each power of x must be equal in order that the equation be true for all values of x.
So now clear fractions (and ignore the denominator) so that you get
Ax2 + 2Ax + 3A +
Bx2 - Bx +
Cx2 + 3Cx
which gives you
A+B+C=0
2A-B+3C=0
3A=1
then A= 1/3
Substitute to get 2 equations in the unknowns B and C...and solve
Then each one of the fractions in the second line above will integrate as a ln which you can then collect.