
Yefim S. answered 02/02/21
Math Tutor with Experience
WE create vectors: AB = <7, 8, 1> and AC = <2, 1, 1>.
Now area S = 1/2IABxACI;
Ii j kI
ABxAC = I7 8 1I = 7i - 5j - 9k
I2 1 1I
Then area of triangle S = 1/2(72 +(-5)2 + (-9)2)1/2 = 6.22495
Yefim S. answered 02/02/21
Math Tutor with Experience
WE create vectors: AB = <7, 8, 1> and AC = <2, 1, 1>.
Now area S = 1/2IABxACI;
Ii j kI
ABxAC = I7 8 1I = 7i - 5j - 9k
I2 1 1I
Then area of triangle S = 1/2(72 +(-5)2 + (-9)2)1/2 = 6.22495
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