The substitution t= a sin θ will get you the integral as (x/2)sqrt(16-x2) + 8 arcsin x/4
This function has DOMAIN [0,4] and range is [0,4π] which assumes you have restricted the domain as noted.
Nic C.
asked 02/02/21Find the range of the function
.
| [-4, 4] | |
| [0, 4] | |
| [0, 4π] | |
| [0, 8π] |
The substitution t= a sin θ will get you the integral as (x/2)sqrt(16-x2) + 8 arcsin x/4
This function has DOMAIN [0,4] and range is [0,4π] which assumes you have restricted the domain as noted.
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