
Yefim S. answered 02/02/21
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Let find 1st domain of this function: x2 - 4 ≥ 0 and x2 + x - 6 ≠ 0; x ≤ - 2 or x ≥ 2; x ≠ - 3 and x ≠ 2.
So domain: (-∞, -3)U(-3, -2]U(2, ∞).
Now this function continuous on intervals (- ∞, -3), (-3,-2), (2, ∞).
At x = -3 and x = 2 we have infinite discontinuity